Winkel im Dreieck
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
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Exercise:
Wie gross sind die Winkel im Dreieck mit den Eckpunkten AAx|Ay|Az BBx|By|Bz und CCx|Cy|Cz?
Solution:
tdplotsetmaincoords center tikzpicturelatex scale. tdplot_main_coords tikzsetscaled unit vectors. foreach x in --... drawcolorgray scaled cs x---x; foreach y in --... drawcolorgray scaled cs -y--y; drawcolorgreen!!black- scaled cs --- noderight small bmx; drawcolorgreen!!black- scaled cs --- nodeabove small bmy; drawcolorgreen!!black- scaled cs --- nodeleft small bmz; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesAxXAyXAzX noderightblue tiny AAx|Ay|Az; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesBxXByXBzX nodeaboveblue tiny BBx|By|Bz; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesCxXCyXCzX nodebelowblue tiny CCx|Cy|Cz; drawcolorred!!blue scaled cs AxXAyXAzX--BxXByXBzX nodemidway right tiny vec c; drawcolorred!!blue scaled cs AxXAyXAzX--CxXCyXCzX nodemidway right tiny vec b; drawcolorred!!blue scaled cs CxXCyXCzX--BxXByXBzX nodemidway left tiny vec a; tikzpicture center bf Berechnung von alpha sphericalangle BAC Um den Winkel berechnen zu können müssen zuerst vecAB und vecAC ermittelt werden: vecAB vecOB-vecOA pmatrix BxX ByX BzXpmatrix-pmatrix AxX AyX AzXpmatrix pmatrix axX ayX azXpmatrix vecAC vecOC-vecOA pmatrix CxX CyX CzXpmatrix-pmatrix AxX AyX AzXpmatrix pmatrix cxX cyX czXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosalpha fracvecAB vecAC|vecAB| |vecAC| fracpmatrix axX ayX azXpmatrix pmatrix cxX cyX czXpmatrixleft|pmatrix axX ayX azXpmatrixright| left|pmatrix cxX cyX czXpmatrixright| fracsxXsyXszXsqrtaxX^+ayX^+azX^ sqrtcxX^+cyX^+czX^ fracSXsqrtTX sqrtUX alpha arccosfracSXsqrtTX sqrtUX arccosfrac-sqrt arccosfrac-sqrt ang bf Berechnung von beta sphericalangle ABC Um den Winkel berechnen zu können müssen auch hier wieder zuerst vecBA und vecBC ermittelt werden: vecBA vecOA-vecOB pmatrix AxX AyX AzXpmatrix-pmatrix BxX ByX BzXpmatrix pmatrix dxX dyX dzXpmatrix vecBC vecOC-vecOB pmatrix CxX CyX CzXpmatrix-pmatrix BxX ByX BzXpmatrix pmatrix exX eyX ezXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosbeta fracvecBA vecBC |vecBA| |vecBC| fracpmatrix dxX dyX dzXpmatrix pmatrix exX eyX ezXpmatrixleft|pmatrix dxX dyX dzXpmatrixright| left|pmatrix exX eyX ezXpmatrixright| fracvxX+vyX+vzXsqrtdxX^+dyX^+dzX^ sqrtexX^+eyX^+ezX^ fracVXsqrtWX sqrtXX beta arccosfracVXsqrtWX sqrtXX arccosfracsqrt ang. bf Berechnung von gamma sphericalangle ACB Um den Winkel berechnen zu können müssen auch hier wieder zuerst vecCA und vecCB ermittelt werden: vecCA vecOA-vecOC pmatrix AxX AyX AzXpmatrix-pmatrix CxX CyX CzXpmatrix pmatrix fxX fyX fzXpmatrix vecCB vecOB-vecOC pmatrix BxX ByX BzXpmatrix-pmatrix CxX CyX CzXpmatrix pmatrix gxX gyX gzXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosgamma fracvecCA vecCB |vecCA| |vecCB| fracpmatrix fxX fyX fzXpmatrix pmatrix gxX gyX gzXpmatrixleft|pmatrix fxX fyX fzXpmatrixright| left|pmatrix gxX gyX gzXpmatrixright| fracwxX+wyX+wzXsqrtfxX^+fyX^+fzX^ sqrtgxX^+gyX^+gzX^ fracYXsqrtZX sqrtAX gamma arccosfracYXsqrtZX sqrtAX ang.
Wie gross sind die Winkel im Dreieck mit den Eckpunkten AAx|Ay|Az BBx|By|Bz und CCx|Cy|Cz?
Solution:
tdplotsetmaincoords center tikzpicturelatex scale. tdplot_main_coords tikzsetscaled unit vectors. foreach x in --... drawcolorgray scaled cs x---x; foreach y in --... drawcolorgray scaled cs -y--y; drawcolorgreen!!black- scaled cs --- noderight small bmx; drawcolorgreen!!black- scaled cs --- nodeabove small bmy; drawcolorgreen!!black- scaled cs --- nodeleft small bmz; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesAxXAyXAzX noderightblue tiny AAx|Ay|Az; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesBxXByXBzX nodeaboveblue tiny BBx|By|Bz; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesCxXCyXCzX nodebelowblue tiny CCx|Cy|Cz; drawcolorred!!blue scaled cs AxXAyXAzX--BxXByXBzX nodemidway right tiny vec c; drawcolorred!!blue scaled cs AxXAyXAzX--CxXCyXCzX nodemidway right tiny vec b; drawcolorred!!blue scaled cs CxXCyXCzX--BxXByXBzX nodemidway left tiny vec a; tikzpicture center bf Berechnung von alpha sphericalangle BAC Um den Winkel berechnen zu können müssen zuerst vecAB und vecAC ermittelt werden: vecAB vecOB-vecOA pmatrix BxX ByX BzXpmatrix-pmatrix AxX AyX AzXpmatrix pmatrix axX ayX azXpmatrix vecAC vecOC-vecOA pmatrix CxX CyX CzXpmatrix-pmatrix AxX AyX AzXpmatrix pmatrix cxX cyX czXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosalpha fracvecAB vecAC|vecAB| |vecAC| fracpmatrix axX ayX azXpmatrix pmatrix cxX cyX czXpmatrixleft|pmatrix axX ayX azXpmatrixright| left|pmatrix cxX cyX czXpmatrixright| fracsxXsyXszXsqrtaxX^+ayX^+azX^ sqrtcxX^+cyX^+czX^ fracSXsqrtTX sqrtUX alpha arccosfracSXsqrtTX sqrtUX arccosfrac-sqrt arccosfrac-sqrt ang bf Berechnung von beta sphericalangle ABC Um den Winkel berechnen zu können müssen auch hier wieder zuerst vecBA und vecBC ermittelt werden: vecBA vecOA-vecOB pmatrix AxX AyX AzXpmatrix-pmatrix BxX ByX BzXpmatrix pmatrix dxX dyX dzXpmatrix vecBC vecOC-vecOB pmatrix CxX CyX CzXpmatrix-pmatrix BxX ByX BzXpmatrix pmatrix exX eyX ezXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosbeta fracvecBA vecBC |vecBA| |vecBC| fracpmatrix dxX dyX dzXpmatrix pmatrix exX eyX ezXpmatrixleft|pmatrix dxX dyX dzXpmatrixright| left|pmatrix exX eyX ezXpmatrixright| fracvxX+vyX+vzXsqrtdxX^+dyX^+dzX^ sqrtexX^+eyX^+ezX^ fracVXsqrtWX sqrtXX beta arccosfracVXsqrtWX sqrtXX arccosfracsqrt ang. bf Berechnung von gamma sphericalangle ACB Um den Winkel berechnen zu können müssen auch hier wieder zuerst vecCA und vecCB ermittelt werden: vecCA vecOA-vecOC pmatrix AxX AyX AzXpmatrix-pmatrix CxX CyX CzXpmatrix pmatrix fxX fyX fzXpmatrix vecCB vecOB-vecOC pmatrix BxX ByX BzXpmatrix-pmatrix CxX CyX CzXpmatrix pmatrix gxX gyX gzXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosgamma fracvecCA vecCB |vecCA| |vecCB| fracpmatrix fxX fyX fzXpmatrix pmatrix gxX gyX gzXpmatrixleft|pmatrix fxX fyX fzXpmatrixright| left|pmatrix gxX gyX gzXpmatrixright| fracwxX+wyX+wzXsqrtfxX^+fyX^+fzX^ sqrtgxX^+gyX^+gzX^ fracYXsqrtZX sqrtAX gamma arccosfracYXsqrtZX sqrtAX ang.
Meta Information
Exercise:
Wie gross sind die Winkel im Dreieck mit den Eckpunkten AAx|Ay|Az BBx|By|Bz und CCx|Cy|Cz?
Solution:
tdplotsetmaincoords center tikzpicturelatex scale. tdplot_main_coords tikzsetscaled unit vectors. foreach x in --... drawcolorgray scaled cs x---x; foreach y in --... drawcolorgray scaled cs -y--y; drawcolorgreen!!black- scaled cs --- noderight small bmx; drawcolorgreen!!black- scaled cs --- nodeabove small bmy; drawcolorgreen!!black- scaled cs --- nodeleft small bmz; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesAxXAyXAzX noderightblue tiny AAx|Ay|Az; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesBxXByXBzX nodeaboveblue tiny BBx|By|Bz; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesCxXCyXCzX nodebelowblue tiny CCx|Cy|Cz; drawcolorred!!blue scaled cs AxXAyXAzX--BxXByXBzX nodemidway right tiny vec c; drawcolorred!!blue scaled cs AxXAyXAzX--CxXCyXCzX nodemidway right tiny vec b; drawcolorred!!blue scaled cs CxXCyXCzX--BxXByXBzX nodemidway left tiny vec a; tikzpicture center bf Berechnung von alpha sphericalangle BAC Um den Winkel berechnen zu können müssen zuerst vecAB und vecAC ermittelt werden: vecAB vecOB-vecOA pmatrix BxX ByX BzXpmatrix-pmatrix AxX AyX AzXpmatrix pmatrix axX ayX azXpmatrix vecAC vecOC-vecOA pmatrix CxX CyX CzXpmatrix-pmatrix AxX AyX AzXpmatrix pmatrix cxX cyX czXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosalpha fracvecAB vecAC|vecAB| |vecAC| fracpmatrix axX ayX azXpmatrix pmatrix cxX cyX czXpmatrixleft|pmatrix axX ayX azXpmatrixright| left|pmatrix cxX cyX czXpmatrixright| fracsxXsyXszXsqrtaxX^+ayX^+azX^ sqrtcxX^+cyX^+czX^ fracSXsqrtTX sqrtUX alpha arccosfracSXsqrtTX sqrtUX arccosfrac-sqrt arccosfrac-sqrt ang bf Berechnung von beta sphericalangle ABC Um den Winkel berechnen zu können müssen auch hier wieder zuerst vecBA und vecBC ermittelt werden: vecBA vecOA-vecOB pmatrix AxX AyX AzXpmatrix-pmatrix BxX ByX BzXpmatrix pmatrix dxX dyX dzXpmatrix vecBC vecOC-vecOB pmatrix CxX CyX CzXpmatrix-pmatrix BxX ByX BzXpmatrix pmatrix exX eyX ezXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosbeta fracvecBA vecBC |vecBA| |vecBC| fracpmatrix dxX dyX dzXpmatrix pmatrix exX eyX ezXpmatrixleft|pmatrix dxX dyX dzXpmatrixright| left|pmatrix exX eyX ezXpmatrixright| fracvxX+vyX+vzXsqrtdxX^+dyX^+dzX^ sqrtexX^+eyX^+ezX^ fracVXsqrtWX sqrtXX beta arccosfracVXsqrtWX sqrtXX arccosfracsqrt ang. bf Berechnung von gamma sphericalangle ACB Um den Winkel berechnen zu können müssen auch hier wieder zuerst vecCA und vecCB ermittelt werden: vecCA vecOA-vecOC pmatrix AxX AyX AzXpmatrix-pmatrix CxX CyX CzXpmatrix pmatrix fxX fyX fzXpmatrix vecCB vecOB-vecOC pmatrix BxX ByX BzXpmatrix-pmatrix CxX CyX CzXpmatrix pmatrix gxX gyX gzXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosgamma fracvecCA vecCB |vecCA| |vecCB| fracpmatrix fxX fyX fzXpmatrix pmatrix gxX gyX gzXpmatrixleft|pmatrix fxX fyX fzXpmatrixright| left|pmatrix gxX gyX gzXpmatrixright| fracwxX+wyX+wzXsqrtfxX^+fyX^+fzX^ sqrtgxX^+gyX^+gzX^ fracYXsqrtZX sqrtAX gamma arccosfracYXsqrtZX sqrtAX ang.
Wie gross sind die Winkel im Dreieck mit den Eckpunkten AAx|Ay|Az BBx|By|Bz und CCx|Cy|Cz?
Solution:
tdplotsetmaincoords center tikzpicturelatex scale. tdplot_main_coords tikzsetscaled unit vectors. foreach x in --... drawcolorgray scaled cs x---x; foreach y in --... drawcolorgray scaled cs -y--y; drawcolorgreen!!black- scaled cs --- noderight small bmx; drawcolorgreen!!black- scaled cs --- nodeabove small bmy; drawcolorgreen!!black- scaled cs --- nodeleft small bmz; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesAxXAyXAzX noderightblue tiny AAx|Ay|Az; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesBxXByXBzX nodeaboveblue tiny BBx|By|Bz; shadedrawscaled cs plot only marks mark* mark sizept mark optionsfillblue!!white coordinatesCxXCyXCzX nodebelowblue tiny CCx|Cy|Cz; drawcolorred!!blue scaled cs AxXAyXAzX--BxXByXBzX nodemidway right tiny vec c; drawcolorred!!blue scaled cs AxXAyXAzX--CxXCyXCzX nodemidway right tiny vec b; drawcolorred!!blue scaled cs CxXCyXCzX--BxXByXBzX nodemidway left tiny vec a; tikzpicture center bf Berechnung von alpha sphericalangle BAC Um den Winkel berechnen zu können müssen zuerst vecAB und vecAC ermittelt werden: vecAB vecOB-vecOA pmatrix BxX ByX BzXpmatrix-pmatrix AxX AyX AzXpmatrix pmatrix axX ayX azXpmatrix vecAC vecOC-vecOA pmatrix CxX CyX CzXpmatrix-pmatrix AxX AyX AzXpmatrix pmatrix cxX cyX czXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosalpha fracvecAB vecAC|vecAB| |vecAC| fracpmatrix axX ayX azXpmatrix pmatrix cxX cyX czXpmatrixleft|pmatrix axX ayX azXpmatrixright| left|pmatrix cxX cyX czXpmatrixright| fracsxXsyXszXsqrtaxX^+ayX^+azX^ sqrtcxX^+cyX^+czX^ fracSXsqrtTX sqrtUX alpha arccosfracSXsqrtTX sqrtUX arccosfrac-sqrt arccosfrac-sqrt ang bf Berechnung von beta sphericalangle ABC Um den Winkel berechnen zu können müssen auch hier wieder zuerst vecBA und vecBC ermittelt werden: vecBA vecOA-vecOB pmatrix AxX AyX AzXpmatrix-pmatrix BxX ByX BzXpmatrix pmatrix dxX dyX dzXpmatrix vecBC vecOC-vecOB pmatrix CxX CyX CzXpmatrix-pmatrix BxX ByX BzXpmatrix pmatrix exX eyX ezXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosbeta fracvecBA vecBC |vecBA| |vecBC| fracpmatrix dxX dyX dzXpmatrix pmatrix exX eyX ezXpmatrixleft|pmatrix dxX dyX dzXpmatrixright| left|pmatrix exX eyX ezXpmatrixright| fracvxX+vyX+vzXsqrtdxX^+dyX^+dzX^ sqrtexX^+eyX^+ezX^ fracVXsqrtWX sqrtXX beta arccosfracVXsqrtWX sqrtXX arccosfracsqrt ang. bf Berechnung von gamma sphericalangle ACB Um den Winkel berechnen zu können müssen auch hier wieder zuerst vecCA und vecCB ermittelt werden: vecCA vecOA-vecOC pmatrix AxX AyX AzXpmatrix-pmatrix CxX CyX CzXpmatrix pmatrix fxX fyX fzXpmatrix vecCB vecOB-vecOC pmatrix BxX ByX BzXpmatrix-pmatrix CxX CyX CzXpmatrix pmatrix gxX gyX gzXpmatrix Anschliess kann mithilfe des Skalarproduktes der gesuchte Winkel berechnet werden: cosgamma fracvecCA vecCB |vecCA| |vecCB| fracpmatrix fxX fyX fzXpmatrix pmatrix gxX gyX gzXpmatrixleft|pmatrix fxX fyX fzXpmatrixright| left|pmatrix gxX gyX gzXpmatrixright| fracwxX+wyX+wzXsqrtfxX^+fyX^+fzX^ sqrtgxX^+gyX^+gzX^ fracYXsqrtZX sqrtAX gamma arccosfracYXsqrtZX sqrtAX ang.
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